16kim 16kim
  • 24-04-2016
  • Mathematics
contestada

what is the solution for the following equation?
x^2-6x+9=11

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apologiabiology
apologiabiology apologiabiology
  • 24-04-2016
make one side equal zero
minus 11 to both sides
x^2-6x-2=0
another quadratic equation

if you hahve
ax^2+bx+c=0
x=[tex] \frac{-b+/- \sqrt{b^{2}-4ac} }{2a} [/tex]

1x^2-6x-2=0
a=1
b=-6
c=-2

x=[tex] \frac{-(-6)+/- \sqrt{(-6)^{2}-4(1)(-2)} }{2(1)} [/tex]
x=[tex] \frac{6+/- \sqrt{36+8} }{2} [/tex]
x=[tex] \frac{6+/- \sqrt{44} }{2} [/tex]
x=[tex] \frac{6+/- 2\sqrt{11} }{2} [/tex]
x=[tex] 3+/- \sqrt{11}[/tex]
x=[tex] 3+ \sqrt{11}[/tex] or [tex] 3- \sqrt{11}[/tex]

aprox
x=6.31662 or -0.316625
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