We have the following functions:
f (x) = 3x ^ 2-1
g (x) = x + 2
Adding both functions we have:
(f + g) (x) = f (x) + g (x)
(f + g) (x) = (3x ^ 2-1) + (x + 2)
(f + g) (x) = 3x ^ 2 + x + 1
Answer:
The answer for this case is given by:
(f + g) (x) = 3x ^ 2 + x + 1
option 3
