[tex]5 \times \dfrac{9}{1} = 51 x \div 9 - 3[/tex]
[tex]\dfrac{5}{1} \times \dfrac{9}{1} = \dfrac{51x}{9}- 3[/tex]
[tex]45 = \dfrac{51x}{9} - 3[/tex]
[tex]45 + 3= \dfrac{51x}{9}[/tex]
[tex]48 = \dfrac{51x}{9}[/tex]
[tex]51 x = 48 \times 9
[/tex]
[tex]51 x = 432[/tex]
[tex]x = \dfrac{432}{17} [/tex]
[tex]x = 8\dfrac{8}{17} [/tex]
