Hey there!
If [tex]a = 21 , z = 7, b = 3, w = 6 [/tex]
Then our whole problem change
We get: [tex] \frac{21}{7} +(3)(6)^2 \\ \\ \frac{21}{7} = 3 \\ \\ (3)(6)^2 = 108 \\ \\ \\ \\ 3 + 108 = 111 \\ \\ \\ \\ \\ Answer: 111 [/tex]
Good luck on your assignment and enjoy your day!
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