Respuesta :

konrad509
[tex]x^2-3x+2=0\\ x^2-x-2x+2=0\\ x(x-1)-2(x-1)=0\\ (x-2)(x-1)=0\\ x=2 \vee x=1\\\\\ x^2-3x+2=0\\ x^2-3x+\frac{9}{4}-\frac{1}{4}=0\\ (x-\frac{3}{2})^2=\frac{1}{4}\\ x-\frac{3}{2}=\sqrt{\frac{1}{4}} \vee x-\frac{3}{2}=-\sqrt{\frac{1}{4}}\\ x-\frac{3}{2}=\frac{1}{2} \vee x-\frac{3}{2}=-\frac{1}{2}\\ x=\frac{4}{2} \vee x=\frac{2}{2}\\ x=2 \vee x=1[/tex]

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