The answer is 0.80 Mol C2H6O is in a 37.0 g sample. To do this take Carbon and times its average atomic mass by 2, do the same for hydrogen and Oxygen. Then add the answers together.Then put it into the equation (37.0 C2H6O)*(1 mol C2H6O/46.02 C2H6O) = 0.80 mol C2H6O
