Respuesta :

[tex]\bf \sqrt{\cfrac{80w^3}{9}}\implies \cfrac{\sqrt{80w^3}}{\sqrt{9}}\qquad \boxed{80=16\cdot 5}\qquad \cfrac{\sqrt{16\cdot 5w^{2+1}}}{\sqrt{9}} \\\\\\ \cfrac{\sqrt{4^2\cdot 5w^2w^1}}{\sqrt{9}}\implies \cfrac{4w\sqrt{5w}}{3}[/tex]
sheldonmeki04

Answer:

The answer to the question is

 

4w√5w

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