Respuesta :

IssacAsimov
[tex] \sqrt{-4} [/tex] can also be written as 2i 
where i = √-1

[tex] \frac{2i}{4-2-3i} = \frac{2i}{2-3i} [/tex]

Rationalizing denominator,

[tex] \frac{2i(2+3i)}{(2-3i)(2+3i)} = \frac{4i-6}{4+9} = \frac{4i-6}{13} [/tex]