Answer: D. 19, 13, 3, -11, -29
Step-by-step explanation:
The first five terms can be found by taking n= 1,2,3,4,5
The given sequence is :
[tex]a_{n} =21-2n^{2}[/tex]
Substituting n = 1,2,3,4,5 we have :
[tex]a_{1} =21-2(1^{2} )=21-2=19.[/tex]
[tex]a_{2} =21-2(2^{2} )=21-8=13[/tex]
[tex]a_{3} =21-2(3^{2} )=21-18=3[/tex]
[tex]a_{4} =21-2(4^{2} )=21-32=-11[/tex]
[tex]a_{5} =21-2(5^{2} )=21-50=-29[/tex]
The first five terms of the sequence are
D. 19, 13, 3, -11, -29
