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A block with a mass of 30 kg is located on a horizontal, frictionless tabletop. this block is connected by a rope to another block with a mass of 10 kg. the rope is looped through a pulley on the table's edge so that the less massive block is hanging over the edge. what is the magnitude of the acceleration of the larger block across the table

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Yna9141
The net force that acts on the larger block is equal to the weight of the smaller block which can be calculated through the equation,
    W = m x g

where W is weight, m is the smaller mass, and g is the acceleration due to gravity. Substituting the known values,
   W = (10 kg)(9.8 m/s²) = 98 N

Then, the net force is,
   F = M x a

where F is the net force, M is the larger mass, and a is the acceleration.
    98N = (30) x a

    a = 3.2 m/s²

ANSWER: a = 3.2 m/s²

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