Respuesta :

ValyRemus
[tex]a+ \frac{8}{3}= \frac{2}{3}\\\\a= \frac{2}{3}- \frac{8}{3}\\\\a= \frac{-6}{3}\\\\\boxed{a=-2}[/tex]
[tex]a+\frac{8}{3}=\frac{2}{3}\ \ \ \ |subtract\ \frac{8}{3}\ from\ both\ sides\\\\a+\frac{8}{3}-\frac{8}{3}=\frac{2}{3}-\frac{8}{3}\\\\a=\frac{2-8}{3}\\\\\boxed{a=\frac{-6}{3}\to a=-\frac{6}{3}\to \boxed{a=-2}}[/tex]

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