alexismolina121 alexismolina121
  • 24-08-2017
  • Mathematics
contestada

Which equation is the inverse of y = 2x2 – 8?

Respuesta :

nap14hockey
nap14hockey nap14hockey
  • 24-08-2017
x=2y^2 -8
or
2y^2= x+8
y^2 = (x+8)/2

[tex]y = \sqrt{ \frac{x+8}{2} } [/tex]
Answer Link
calculista
calculista calculista
  • 25-09-2018

we have

[tex]y=2x^{2} -8[/tex]

Step [tex]1[/tex]

Exchanges the variable x for y and the variable y for x

[tex]x=2y^{2} -8[/tex]

Step [tex]2[/tex]

Clear the variable y

[tex]2y^{2}=x+8[/tex]

[tex]y^{2}=\frac{x+8}{2} \\ \\y=(+/-)\sqrt{\frac{x+8}{2}}[/tex]

so

the inverse is equal to-------> [tex]y=(+/-)\sqrt{\frac{x+8}{2}}[/tex]

therefore

the answer is

[tex]y=(+/-)\sqrt{\frac{x+8}{2}}[/tex]

Answer Link

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