Let the numbers be a and b.
The sum of the numbers is 120, so we have: i) a+b=120
Four times the larger divided by twice the smaller is thirty-four:
assume the larger is a :
ii)
[tex] \frac{4a}{2b}=34\\\\ \frac{2a}{b}=34\\\\2a=34b\\\\a=17b [/tex]
substitute a=17b in the first equation:
a+b=120
17b+b=120
18b=120
b=120/18=60/9=20/3
thus, a=17b=17(20/3)=340/3
Answer: 20/3, 340/3
