dominicpepiton
dominicpepiton dominicpepiton
  • 23-06-2017
  • Mathematics
contestada

Solve the following equation. Then place the correct number in the box provided. 2(x + 1 ) - 3(x + 5) ≥ 0

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lanna213
lanna213 lanna213
  • 23-06-2017
when you divide by a negative make sure you switch the sign to the opposite side
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FelisFelis FelisFelis
  • 21-10-2019

Answer:

The required solution is [tex]x \leq -13[/tex]

Step-by-step explanation:

Consider the provide inequality.

[tex]2(x + 1 ) - 3(x + 5) \geq0[/tex]

Open the parentheses.

[tex]2x + 2 - 3x - 15 \geq 0[/tex]

Add and subtract the like terms.

[tex]-x -13 \geq 0[/tex]

Add 13 to the both side.

[tex]-x \geq 13[/tex]

Multiply both the sides by -1 and reverse the inequality.

[tex]x \leq -13[/tex]

Hence, the required solution is [tex]x \leq -13[/tex]

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