Respuesta :

[tex]\bf \textit{area of a sector of a circle}\\\\ A=\cfrac{\theta\pi r^2}{360}\qquad \begin{cases} \theta=\textit{angle in degrees}\\ r=radius\\ ----------\\ \theta=168\\ r=8 \end{cases}\implies A=\cfrac{168\cdot \pi \cdot 8^2}{360}[/tex]
SPYSEYNOCHOS
93.8 [tex]in^{2} [/tex]

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