Given: Diagram
Required: Area of figure.
Explanation:
The given figure can be divided into 3 parts.
The bottomost rectangle (by extending the 3 cm line to 10 cm line).
It has dimenions 3 cm and 2 cm as given.
Middle rectangle, with length 7 cm and breadth 3cm + 2cm = 5cm.
Topmost right triangle, with height 3 cm and base 3cm +2cm = 5cm
So area of figure is areas of these 3 parts.
Area of topmost triangle =
[tex]\begin{gathered} A_1=\frac{1}{2}(5)(3) \\ A_1=\frac{15}{2}=7.5\text{ sqcm} \end{gathered}[/tex]
Area of middle rectangle
[tex]\begin{gathered} A_2=7\times5 \\ A_2=35\text{ sqcm} \end{gathered}[/tex]
Area of bottom rectangle
[tex]\begin{gathered} A_3=3\times2 \\ A_3=6sq\text{ .cm} \end{gathered}[/tex]
So total area is
[tex]\begin{gathered} A=A_1+A_2+A_3 \\ A=7.5+35+6=48.5\text{ sq.cm} \end{gathered}[/tex]
Final Answer: Area is 48.5 square centimeters.
