Given data
*The given velocity of the car is v(t)= 10 + 3t + 512
The acceleration of the car is calculated as
[tex]\begin{gathered} a(t)=\frac{d}{dt}(v(t)) \\ =\frac{d}{dt}(10+3t+512) \\ =3m/s^2 \end{gathered}[/tex]Thus, the acceleration of the car at t = 2 s is 3 m/s^2
