Solution:
Given the logarithmic expression:
[tex]\log_545[/tex]
According to the change of base formula,
[tex]\log_BA=\frac{\ln A}{\ln\text{ B}}[/tex]
Thus, expressing the logarithm expression in a natural logarithm,
[tex]\log_545=\frac{\ln45}{\ln5}[/tex]
Hence, we have
[tex]\frac{\ln45}{\ln5}[/tex]
