Answer:
The angle A for the first question is equal to 43.6 degrees
Step-by-step explanation:
1st step:
[tex]\frac{sin\theta}{20} \times \frac{sin 90}{29}[/tex]
2nd step:
Take 20 to the other side.
[tex]sin \theta = \frac{20(sin90)}{29}[/tex]
3rd step:
Solve the right side and then take the inverse sin of the right side to get the value of theta and you get 43.6 degrees
[tex]\theta = 43.6[/tex]
