The concentration of S2−in equilibrium with MnS(s) (sp=4. 6×10−14) and 0.083M Mn2+ is mathematically given as
[s^2-]=61.333*10^{-14}M
What is the concentration of S2−?
Generally, the equation for the solubility constant is mathematically given as
Ksp=[Mn^2+][s^2-]
Therefore
4.6*10^{-14}=0.075*[s^2-]
[s^2-]=4500/0.075*10{-14}
[s^2-]=61.333*10^{-14}M
In conclusion, The concentration of S2−
[s^2-]=61.333*10^{-14}M
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