for ax²+bx+c=0
x=[tex] \frac{-b+/- \sqrt{b^2-4ac} }{2a} [/tex]
so
12x²-17x+6=0
a=12
b=-17
c=6
x=[tex] \frac{-(-17)+/- \sqrt{(-17)^2-4(12)(6)} }{2(12)} [/tex]
x=[tex] \frac{17+/- \sqrt{289-288} }{24} [/tex]
x=[tex] \frac{17+/- \sqrt{1} }{24} [/tex]
x=[tex] \frac{17+/- 1}{32} [/tex]
x=[tex] \frac{17+1}{32} [/tex] or [tex] \frac{17-1}{32} [/tex]
x=[tex] \frac{18}{32} [/tex] or [tex] \frac{16}{32} [/tex]
x=9/16 or 1/2
