Respuesta :

chetankachana

Answer:

[tex]y = \frac83, y = -\frac83[/tex]

Step-by-step explanation:

Solve:

  • [tex]64y = 9y^3[/tex]
  • [tex]64 = 9y^2 \text{ divide both sides by y}[/tex]
  • [tex]\frac{64}{9} = y^2 \text{ divide both sides by 9}[/tex]
  • [tex]\sqrt{\frac{64}{9}} = \sqrt{y^2}[/tex]
  • [tex]\frac83 = |y|[/tex]
  • [tex]y = \frac83, y = -\frac83[/tex]

Use rule: √a² = |a|

-Chetan k

boatengalbert291
64 = 9y^3

Divide through by 9y

64/9=y^2

y^2=64/9

y= √(64/9) or -√(64/9)

y=8/3 or -8/3
y=2 2/3 or -2 2/3

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