The speed of the elevator after it has moved downward is 4.43 m/s.
Conservation of mechanical energy
The speed of the elevator after the impact can be determined by applying the principle of conservation of mechanical energy as shown below;
K.E = P.E
¹/₂mv² = mgh
¹/₂v² = gh
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 1)
v = 4.43 m/s
Thus, the speed of the elevator after it has moved downward is 4.43 m/s.
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