[tex]8x - 1 < 15 \\ 8x < 15 + 1 \\ 8x < 16 \\ x < \frac{16}{8} \\ x < 2[/tex]
Answer:
As Per Given Information
The given equation is 8x-1 <15
Adding both side 1 we obtain
↝ 8x - 1 + 1 < 15 + 1
↝ 8x < 16
Now dividing both side by 8 we obtain
↝ x < 2
So, the required answer is x < 2.
