Step-by-step explanation:
first find out the area of sector ECF
π(10)² × 40°/360°
=100π×1/9
=100π/9 m²
now find the area of sector DCG
π(2)² × 40°/360°
=4π/9 m²*
so the area of the shaded region would be the big sector minus the small sector
so
100π/9 - 4π/9
=96π/9
=33.5 m² (3sig.fig.)
*Note that 4π/9 DOES NOT equal to 2π/3
4/9 DOES NOT EQUAL TO 2/3
