Answer:
See below which answer is most appropriate
Step-by-step explanation:
If you mean [tex]9^{x-1}=2[/tex]:
[tex]9^{x-1}=2[/tex]
[tex]x-1=log_9(2)[/tex]
[tex]x=log_9(2)+1[/tex]
If you mean [tex]9^x-1=2[/tex]:
[tex]9^x-1=2[/tex]
[tex]9^x=3[/tex]
[tex]3^{2x}=3[/tex]
[tex]2x=1[/tex]
[tex]x=\frac{1}{2}[/tex]
