weeaboo4life
weeaboo4life weeaboo4life
  • 24-08-2021
  • Mathematics
contestada

Solve. Tell whether the equations have all real numbers or no solutions.
6k + (3 · 10 – 8) = (2-3)k + 22​

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AmazingA86
AmazingA86 AmazingA86
  • 24-08-2021
The answer is zero, so no solution is your answer.
Answer Link
sqdancefan
sqdancefan sqdancefan
  • 24-08-2021

9514 1404 393

Answer:

  one solution:: k = 0

Step-by-step explanation:

The equation simplifies to ...

  6k +22 = -k +22

  7k = 0 . . . . . . . . . . add k-22 to both sides; next, divide by 7

  k = 0 . . . . . . . . one solution

Answer Link

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