Answer:
2nd option
Step-by-step explanation:
Given
- np - 6 ≤ 3(c - 5) ← distribute
- np - 6 ≤ 3c - 15 ( add 6 to both sides )
- np ≤ 3c - 9
Divide both sides by - p , reversing the symbol as a result of dividing by a negative quantity.
n ≥ [tex]\frac{3c-9}{-p}[/tex]
