rnadhikari619
rnadhikari619 rnadhikari619
  • 21-07-2021
  • Mathematics
contestada

prove:
sin²A-cos²B=sin²B-cos²A ​

Respuesta :

rupita098
rupita098 rupita098
  • 21-07-2021

Step-by-step explanation:

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Answer Link
msm555
msm555 msm555
  • 21-07-2021

Answer:

Solution given:

L.H.S

sin²A-cos²B

we have

sin²A=1-cos²A and Cos²B=1-sin²B

now

replacing value

1-cos²A-(1-sin²B)

open bracket

1-cos²A-1+sin²B

keep together like terms

1-1+sin²B-Cos²A

=sin²B-Cos²A

R.H.S

proved.

Answer Link

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