Answer:
P_2 =0.51 atm
Explanation:
Given that:
Volume (V1) = 2.50 L
Temperature (T1) = 298 K
Volume (V2) = 4.50 L
at standard temperature and pressure;
Pressure (P1) = 1 atm
Temperature (T2) = 273 K
Pressure P2 = ??
Using combined gas law:
[tex]\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2} \\ \\ \dfrac{1 *2.5}{298} = \dfrac{P_2*4.5}{273}[/tex]
[tex]0.008389261745 \times 273 = 4.5P_2[/tex]
[tex]P_2 =\dfrac{0.008389261745 \times 273 }{4.5}[/tex]
[tex]P_2 =0.51 \ atm[/tex]
