Answer:
[tex]50\:\text{kg water}[/tex]
Step-by-step explanation:
This question implies the constant rate or proportion of water to mass. Therefore, we can set up the following equation:
[tex]\frac{60}{90}=\frac{x}{75},\\\\x=\frac{75\cdot 60}{90}=\boxed{50\:\text{kg water}}[/tex]
