Answer:
[tex]x = 1+\sqrt{2} = 2.4\\or\\x= 1-\sqrt{2} = -0.4[/tex]
Step-by-step explanation:
[tex]y = x^2-2x+5\\\\6=x^2-2x+5\\\\x^2-2x-1=0\\\\\\\frac{-b+-\sqrt{b^2-4ac} }{2a} = x\\a = 1, b = -2, c = -1\\\\\frac{2+-2\sqrt{2} }{2\\}\\\\x = 1+\sqrt{2} = 2.4\\or\\x= 1-\sqrt{2} = -0.4[/tex]
