Aprieronmandrel Aprieronmandrel
  • 24-11-2016
  • Mathematics
contestada

Find the real zeros of the trigonometric function on the interval 0 ≤ x < 2π

f(x) = 4 cos^2(x) - 3

Respuesta :

syed514
syed514 syed514
  • 27-11-2016
4cos2(x)−3=0

or 
4cos2(x)=3

cos(x)= √3/2

π/6, 5π/6,  7π/6,  11π/6



Answer Link
Edufirst
Edufirst Edufirst
  • 27-11-2016
f(x) = 4 [cos (x)]^2 - 3 = 0

4[cos(x)]^2 = 3

cos(x) = √3 / 2

That happens in the first and fourth quadrants, for the angles 30 degrees and 330 degrees.

Answer: x = 30 degrees and x = 330 degrees
Answer Link

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