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24-11-2016
Mathematics

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Assume the random variable X is normally distributed with a mean of 50 and a standard deviation of 7. Find the 96th percentile.

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syed514 syed514

26-11-2016

90% then z = invNorm(.90) = 1.2816
z = 1.2816 = (X-50)/77(1.2816) + 50 = 8.97 + 50 = X = 59

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