The solution to the problem is as follows:
=lim n->∞ sin(PI/n) / (1/n)
0/0 form : Use L'Hopital's Rule
=lim n->∞ (-PI /n^2)cos(PI/n) /(-1/n^2)
= lim n->∞ PI cos(PI/n)
as n->∞ , cos(PI/n) -> cos(0)=1
so the limits is 'PI'
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