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At 9:00 on Saturday morning, two
bicyclists heading in opposite directions pass each other on a bicycle path. The bicyclist heading north is riding 5
km/hour faster than the bicyclist heading south. At 10:45, they are 47.25 km apart. Find the two bicyclists' rates.
northbound bicyclist = 14 km/h; southbound bicyclist = 7 km/h
northbound bicyclist = 16 km/h; southbound bicyclist = 10 km/h
northbound bicyclist = 16 km/h; southbound bigugelist = 11 km/h
)northbound bicyclist = 18 km/h; southbound bicyclist = 13 km/h

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skyamanda94

Answer:

Step-by-step explanation:

Between 9:00 am and 10:45 am, there have been 1 hour and 45 minutes or 1.75 hours have passed. Let x be the speed of the slower cyclist and x+ 5 be the rate of the second cyclist. The given situation is best represented through the equation below,

                                x(1.75) + (x + 5)(1.75) = 47.25 km

The value of x from the equation is 11. Thus, the two bicyclists' rates are 11 km/h and 16 km/h.

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