Respuesta :

maacastrobr

Answer:

15 g

Explanation:

The reaction that takes place is:

  • 2KCIO₃ → 2KCI + 3O₂

First we convert 25 g of KCIO₃ to moles, using its molar mass:

  • 25 g ÷ 122.55 g/mol = 0.204 mol KCIO₃

Then we convert KCIO₃ moles to KCl moles, using the stoichiometric coefficients:

  • 0.204 mol KCIO₃ * [tex]\frac{2molKCl}{2molKClO_3}[/tex] = 0.204 mol KCl

Finally we convert KCl moles to grams, using the molar mass of KCl:

  • 0.204 mol KCl * 74.55 g/mol = 15.2 g