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23-02-2021
Physics

contestada

A bullet (m = .005 kg) moving at 500 m/s strikes
and sticks in a block of wood (m = 5 kg). What is
the final velocity of the wood/bullet mass?

Respuesta :

yukolof yukolof

23-02-2021

Answer:

fif = 0.01 x 5000 = 50 N

Explanation:

u=150 m/s

v=0

m-10 y =0.01 kg

t=0.03s

s

v=utat

o= 150+a (0.03)

therefore a= -5000 m/s power 2

v power 2 = u power 2 + 2as

0=150 power 2+ 2 x (-5000) x s

therefore f=2.25 m

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