Answer:
67.17 m
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 32 m/s
Angle of projection (θ) = 20°
Acceleration due to gravity (g) = 9.8 m/s²
Range (R) =?
The range can be obtained as follow:
R = u²Sine 2θ / g
R = 32² × Sine (2×20) / 9.8
R = 1024 × Sine 40 / 9.8
R = (1024 × 0.6428) / 9.8
R = 67.17 m
Thus, the range of the ball is 67.17 m
