Answer:
15,16 and 17.
Step-by-step explanation:
Let the three consecutive integers are x, x+1,x+2
ATQ,
x+x+1+x+2=48
3x+3=48
Subtract 3 from both sides,
3x+3-3=48-3
3x=45
x = 15
First integer = 15
Second integer = 15+1 = 16
Third interger = 15+2 = 17
Hence, three integers are 15,16 and 17.
