Answer:
The 25 th term in the sequence
a₂₅ = 56
Step-by-step explanation:
Explanation
Given that the [tex]n^{th}[/tex] term of sequence
aₙ = 8 + 2 ( n-1)
put n =1
a₁ = 8 + 2( 1-1) = 8+0 =8
first term a₁ = 8
put n=2
a₂ = 8 + 2( 2-1) = 8+2 =10
Second term
a₂ = 10
and so on
put n =25
a₂₅ = 8 + 2( 25-1) = 8+2(24) = 8 + 48 = 56
Given sequence
8 , 10 ,.......56,....
