kdcmegan kdcmegan

24-10-2016
Mathematics

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cos(2θ) = 5 sin(θ) − 2

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spinions spinions

24-10-2016

Cos(2[tex]cos2 \alpha = 1-sin^{2} \alpha [/tex].

so...

[tex]1-sin^2\alpha = 5sin\alpha -2 sin^2\alpha + 5sin\alpha -3 = 0[/tex]

Is that what you are trying to do? Find the zeros?

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