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22-10-2016
Chemistry

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calculate mass of caco3 required to liberate 10 litres of co2 at stp

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Willchemistry Willchemistry

23-10-2016

1 mole CaCO3 ----------------- 22.4 L ( at STP)
? mole CaCO3 ----------------- 10 L

10 x 1 / 22.4 => 0.446 moles CaCO3

Molar mass CaCO3 => 100.08 g/mol

1 mole ------------- 100.08 g
0.446 moles ------ ??

0.446 x 100.08 / 1 => 44.635 g

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