Answer:
[tex]V_{rms}=6\sqrt2\ V[/tex]
Explanation:
Given that,
The maximum voltage of an alternating current, [tex]V_{max}=12\ V[/tex]
We need to find the highest Vrms that can be supplied to this component while staying below the voltage limit.
Let rms voltage in terms of peak voltage is given by :
[tex]V_{rms}=\dfrac{V}{\sqrt2}\\\\=\dfrac{12}{\sqrt2}\\\\=\dfrac{12}{\sqrt2}\times \dfrac{\sqrt2}{\sqrt2}\\\\=\dfrac{12\sqrt2}{2}\\\\=6\sqrt2\ V[/tex]
Hence, the required rms voltage is [tex]6\sqrt2\ V[/tex].
