Step-by-step explanation:
the first derivative by using
f’(x)=xn = nx^(n−1)
f(g(x)) = f’(g(x))g’(x)
So f’(x)=2(x⅔ -1)*(2/3 x^(-1/3))=[tex]\frac{4*(x^{\frac{2}{3} }-1) }{3*\sqrt[3]{x} }[/tex]
Second derivative by using:
h’(x)=f(x)*g(x)=f(x) g’(x) + f’(x) g(x)
f’’(x)=
