Step-by-step explanation:
3x-5y =13......eq(1)
x+4y=10....eq (2)
multiply the eq 2 with 3
then it becomes,
3x+12y=30
Subtracting eq2 from eq 1
3x-3x-5y-12y=13-30
-17y=-27
y=1.588
x+6.352=10
x=3.648
Answer:
i am very positive that the answer is 6'1
