Answer:
Step-by-step explanation:
Ok, first put the equation into y=mx+b form
3x-2y=2
subtract 3x from both sides
-2y=-3x+2
divide by -2
y=3/2x-1
Parallel lines have the same slope, but a different y intercpet.
So the new equation so far is y=3/2x+b
Since the line has to pass through the given point, substitute (-6,-2) into the equation
-2=3/2(-6)+b
-2=-9+b
7=b
so the line is y=3/2x+7
