isleyfrazier2004 isleyfrazier2004
  • 21-12-2020
  • Mathematics
contestada

{x{ x + 4<0 or 6x>-12)

Respuesta :

elcharly64
elcharly64 elcharly64
  • 21-12-2020

Answer:

[tex]x\in (-\infty , -4) \cup (-2,+\infty)[/tex]

Step-by-step explanation:

Solve the system of inequalities:

x + 4 < 0

OR:

6x > -12

The first inequality yields the solution:

x < -4

The second inequality gives the solution:

x > -2

The total solution is the disjunction of the individual solutions, i.e., the union of both.

It can be expressed as

[tex]\mathbf{x\in (-\infty , -4) \cup (-2,+\infty)}[/tex]

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