Answer:
a. 5.88 N
b. 5.09 N
Explanation:
Check attachment for drawings of the free-body diagrams.
(a) As we can see on our free-body diagram, the weight force and the normal force are the only forces acting on the y-direction.
Since the bullfrog is in a state of equilibrium, due to it being at rest, we can say that the weight force and normal force are equal to each other.
The weight force w is equal to mg, so we can plug the weight of the frog (0.60 kg) and the force of gravity (9.8 m/s²) to find the weight force.
- w = mg
- w = (0.60 kg)(9.8 m/s²)
- w = 5.88 N
The normal force and the weight force are equal to each other; therefore, the normal force is also equal to 5.88 N.
(b) As seen on the free-body diagram, the two forces that are in the y-direction are the normal force and the y-component of the weight force.
Therefore, by finding the force of the y-component of the weight force, we can find the normal force since they are equal to each other because the bullfrog is not moving up or down.
- F_y = n - w cos(30) = 0
- F_y = n = w cos(30)
We know that the weight force is equal to 5.88 N, so we can plug this value into the y-component for the weight force:
- w cos(30)
- 5.88 * cos(30) = 5.09 N
Since the y-component of the weight force and the normal force are equal to each other, the normal force is also equal to 5.09 N.
