9514 1404 393
Answer:
54w^7/v^17
Step-by-step explanation:
The applicable rules of exponents are ...
(a^b)(a^c) = a^(b+c)
a^-b = 1/a^b
a^0 = 1 . . . . for any a ≠ 0
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[tex]3y^5y^{-5}v^{-9}\cdot6wv^{-8}\cdot3w^6=(3\cdot6\cdot3)v^{-9-8}w^{1+6}y^{5-5}\\\\=54v^{-17}w^7y^0=\boxed{\dfrac{54w^7}{v^{17}}}[/tex]
